First problem instructions. Use the speed and angle to find the horizontal and vertical components of the velocity. This is x and y but beware x is the x component of velocity not x as in distance. This x is how fast it is going in the x or horizontal direction and remember it remains constant. To answer number one you are looking for how long it is in the air and you only need to know how fast it is moving up and down. That is the original vertical velocity or y and the final vertical velocity which is the same as y but down so -y. Also remember that if something moves up and we call that + then down is negative so a = -9.8 m/s2. Use the a=V-Vo/t where a is negative and V is negative. You should get a positive answer. The problem gives you seconds but asks for minutes so convert to minutes at the end.
For number 2 use V=x/t and V is the constant horizontal velocity or x component. You have the time from #1 but make sure you use seconds and not minutes. That should give you the distance x. The problem asks for your answer in km so be sure to convert at the end.
For # 3 if it goes up and comes back down in the given time then it falls down in half the time. Use the x = Vot + 1/2 at2 but for only half the time. That is the time to fall. Since we are only looking at the fall Vo is zero.
First problem instructions. Use the speed and angle to find the horizontal and vertical components of the velocity. This is x and y but beware x is the x component of velocity not x as in distance. This x is how fast it is going in the x or horizontal direction and remember it remains constant. To answer number one you are looking for how long it is in the air and you only need to know how fast it is moving up and down. That is the original vertical velocity or y and the final vertical velocity which is the same as y but down so -y. Also remember that if something moves up and we call that + then down is negative so a = -9.8 m/s2. Use the a=V-Vo/t where a is negative and V is negative. You should get a positive answer. The problem gives you seconds but asks for minutes so convert to minutes at the end.
For number 2 use V=x/t and V is the constant horizontal velocity or x component. You have the time from #1 but make sure you use seconds and not minutes. That should give you the distance x. The problem asks for your answer in km so be sure to convert at the end.
For # 3 if it goes up and comes back down in the given time then it falls down in half the time. Use the x = Vot + 1/2 at2 but for only half the time. That is the time to fall. Since we are only looking at the fall Vo is zero.